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56-15x+x^2=6
We move all terms to the left:
56-15x+x^2-(6)=0
We add all the numbers together, and all the variables
x^2-15x+50=0
a = 1; b = -15; c = +50;
Δ = b2-4ac
Δ = -152-4·1·50
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5}{2*1}=\frac{10}{2} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5}{2*1}=\frac{20}{2} =10 $
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